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craftwizard
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Last seen:2 years 9 months ago
加入:2014-12-17 05:34
Access only allowed App

Hi dialog.

I want to connect only I made 'App'.
Other man-made 'App' should not be connected.
Is there any way for this problem?

Is it possible to force a disconnect in the 'da14580'?
If possible, show me the way.

please help me.

PY_Dialog
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Last seen:2 years 5 months ago
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加入:2014-08-25 09:59
Hi craftwizard,

Hi craftwizard,

There is no way to link app with connection directly. But you can require bonding and set password to identify the peer which you hope to connect.

你可以叫app_disconnect disconnec ()t with peer device after connected.

Regards!
PY

craftwizard
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Last seen:2 years 9 months ago
加入:2014-12-17 05:34
thank PY_Dialog

thank PY_Dialog

"you can require bonding and set password to identify the peer which you hope to connect."
In the sdk, sample code seems not seem.
I need a sample code. Can you send me sample code ?
please help me.

PY_Dialog
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Last seen:2 years 5 months ago
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加入:2014-08-25 09:59
Hi craftwizard,

Hi craftwizard,

The security code will be included in our next version SDK. Could you please wait for some time.

Regards!
PY